design calculation anchor flange - asme viii div 1 app.2

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Design calculation Anchor Flanges According ASME VIII div 1 appendix 2 Customer: IV Oil & Gas Customer ref: OGPA080174-DS-L5400 Date: 10/7/2009 Description: Anchor flange 10" 900# A694 F65 PFF ref 90753546/MV Design data figure mm description de 273 mm Outside diameter welding end di 247.4 mm Inside diameter dfd 12.8 mm Wall thickness welding end rimod 545 mm Flange blade outside diameter fd 70 mm Flange blade thickness bc 470 mm Diameter bolt circle df2 39 mm Bolt holes diameter NB 8 Number of bolts th 270 mm total hight x 368 mm Diameter conical hub re 75 °C Design temperature Rt 244 Rm 530 ca 3 mm Corrosion allowance milt 1 % Mill tolerance TD pd 137 bar Design pressure dsf 0.5 fe 80 kN External axial force me 40.1 kNm External moment Calculated figures FEC = 80000 N [= fe x 1000] MEC = 40100000 N [= me *1000*1000] PDC = 13.7 Mpa [= pd/10] g0 = 9.672 mm [= dfd-dfd x milt / 100 - (minimum wall thickness) 253.528 mm [= di+dfd x milt / 100 + c (Maximum ID) h = 100 mm [= (th-fd)/2] (Hight conical hub) g1 = 57.236 mm [= (x - di)/2] (Average thickness conical hub) h0 = 49.51891372 mm (Square root (max id x minimum WT)) 1) According NEN 3650 N/mm 2 Yield at design temperature 1) N/mm 2 Tensile at 20° Design factor 1) dimax = [= √(dimax x g0)] di de dfd th fd x rimod bc df2 NB, equally spaced Tel. :+31 (0) 168 387410 Fax.:+31 (0) 168 387420 E-Mail : [email protected] Internet: www.pff-group.com PFF Europe B.V . Wielewaalweg 4 4791 PD Klundert The Netherlands

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Page 1: Design Calculation Anchor Flange - ASME VIII Div 1 App.2

Design calculation Anchor FlangesAccording ASME VIII div 1 appendix 2

Customer: IV Oil & GasCustomer ref: OGPA080174-DS-L5400Date: 10/7/2009Description:Anchor flange 10" 900# A694 F65

PFF ref: 90753546/MV

Design data

figure mm description

de 273 mm Outside diameter welding enddi 247.4 mm Inside diameterdfd 12.8 mm Wall thickness welding endrimod 545 mm Flange blade outside diameterfd 70 mm Flange blade thicknessbc 470 mm Diameter bolt circledf2 39 mm Bolt holes diameterNB 8 Number of boltsth 270 mm total hightx 368 mm Diameter conical hubre 75 °C Design temperature

Rt 244

Rm 530ca 3 mm Corrosion allowancemilt 1 % Mill toleranceTDpd 137 bar Design pressure

dsf 0.5fe 80 kN External axial forceme 40.1 kNm External moment

Calculated figures

FEC = 80000 N [= fe x 1000]MEC = 40100000 N [= me *1000*1000]PDC = 13.7 Mpa [= pd/10]g0 = 9.672 mm [= dfd-dfd x milt / 100 - ca] (minimum wall thickness)

253.528 mm [= di+dfd x milt / 100 + ca x 2] (Maximum ID)h = 100 mm [= (th-fd)/2] (Hight conical hub)g1 = 57.236 mm [= (x - di)/2] (Average thickness conical hub)

h0 = 49.51891372 mm (Square root (max id x minimum WT))

N/mm2 Yield at design temperature1)

N/mm2 Tensile at 20°

Design factor1)

dimax =

[= √(dimax x g0)]

di

de

dfd

th fd

x

rimod

bc

df2NB, equally spaced

Tel. :+31 (0) 168 387410Fax.:+31 (0) 168 387420E-Mail : [email protected]: www.pff-group.com

PFF Europe B.V.Wielewaalweg 4

4791 PD KlundertThe Netherlands

Page 2: Design Calculation Anchor Flange - ASME VIII Div 1 App.2

Tel. :+31 (0) 168 387410Fax.:+31 (0) 168 387420E-Mail : [email protected]: www.pff-group.com

PFF Europe B.V.Wielewaalweg 4

4791 PD KlundertThe Netherlands

1) According NEN 3650

Calculation of value Sr, St, & Sh:Values F & v acc. ASME VIII, div 1, appendix 2

e= 0.00980418688 [=F/h0]K= 2.14966394244 [=rimod/di]q= 1 [=1/log(10)]Z1= 0.33237057185 [=log(K)]

t= 1.45256727865

U= 2.95673295569

Y= 2.69063321166

Z= 1.55232521015

D= 16218117.0247

L= 1.18205450788B1= 263.2 [=di + gi] if f<=1 B1=di,max+g0FT= 689422.492401 [=FEC + 4 x MEC / (di + g0)]R= 51 [=(bc-x)/2] 51 if R<0 than R=0M= 71286285.7143 [=FT*(R+g1-g2/2)]

Sr= 92.8558305443

St= 10.2544173454Sh= 69.9429665408 [=f*M/(L*B1*G1)]S1= 81.3993985425 [=(Sh+Sr)/2)]S2= 40.0986919431 [=(Sh+St)/2]FB= 122 [=dsf*Rt]

Results:

Sr = 92.85583054 ≤ FB = 122

St = 10.25441735 ≤ FB = 122

Sh = 69.94296654 ≤ Rt = 244

(Sh + Sr)/2 81.39939854 ≤ FB = 122

(Sh + St)/2 40.09869194 ≤ FB = 122

Conclusion: Accepetable

[=(K2 x (1+8,55246 x q x Z1)-1)/((1,0472 + 1,9448 x K2) x (K-1))

[=K2 x (1 + 8,55246 x q x Z1)-1)/(1,36136 x (K2-1) x (K-1)]

[=(1/(K - 1)) x (0,66845 + 5,7169 x (K2 x q x Z1/(K2 - 1)))]

[=(K2 + 1)/(K2 - 1)]

[=(U/v) x h0 x g02]

[=(fd x e + 1)/t + fd3/D]

[=M*(1,33*fd*e+1)/(L*di*fd2)]

[=Y*M/(di*fd2)-Z*Sr]

N/mm2

N/mm2

N/mm2

N/mm2

N/mm2

Page 3: Design Calculation Anchor Flange - ASME VIII Div 1 App.2

Calculation of value c:

C1 = 0.743141714915908 [=1/3 + (a/12)C2 = 0.367859850722754 [=5/42+17 x a/336]C3 = 0.018422184147991 [=1/210 + a/360]C4 = 0.109809298159183 [=11/360 + 59 x a/5040+(1+3 x a)/c]

C5 = -0.24976860C6 = 0.026297396558733 [=1/120 + 17 x a/5040 + 1/c]

C7 = 1.16770728051034

C8 = 0.165619707296086

C9 = 0.172807418042855

C10 = -0.2616808

C11 = 0.061972734479178

C12 = 0.03664985047907

C13 = 0.017133216195055

C14 = -0.02365974

C15 = 0.007272293164233

C16 = 0.008308374911323

C17 = 0.067414607059023

C18 = -0.2456528449604

C19 = 0.005330402917287

C20 = 0.181732145165333

C21 = -0.2023671

C22 = 0.065809472212013

C23 = -0.38764504

C24 = 0.39240833

C25 = -0.1016443444178

C26 = -3.67100140C27 = -0.54982825 [=C20 - C17 - 5/12 + C17 x C26]C28 = -0.04242218 [=C22 - C19 - 1/12 + C19 x C26]

C29 = -13.47625

C30 = -49.4713374C31 = 10.711641641 [=3 x a/2 - C17 x C30]C32 = 0.763702161310221 [=1/2 - C19 x C30]C33 = -1.98610295 [=0,5 x C26 x C32 + C28 x C31 x C29 - (0,5 x C30 x C28 + C32 x C27 x C29)]C34 = -0.86174432619776 [=1/12 + C18 - C21 - C18 x C26]

C35 = 12.15277478C36 = 0.96736826 [=(C28 x C35 x C29 - C32 x C34 x C29)/C33]C37 = 4.669723334 [=(0,5 x C26 x C35 + C34 x C31 x C29 - (0,5 x C30 x C34 x+ C35 x C27 x C29))/C33]E1 = -0.15554659 [=C17 x C36 + C18 + C19 x C37]E2 = 0.280746812414049 [=C20 x C36 + C21 + C22 x C37]E3 = -0.45723814239761 [=C23 x C36 + C24 + C25 x C37]E4 = 0.706859672204975 [=1/4 + C37/12 + C36/4 - E3/5 - 3 x E2/2 - E1]E5 = 0.0177746 [=E1 x (1/2 + a/6) + E2 x (1/4 + 11 x a/84) + E3 x (1/70 + a/105)]E6 = -0.55937409 [=E5 - C36 x (7/120 + a/36 + 3 x a/c) - 1/40 - a/72 - C37 x (1/60 + a/120 + 1/c)]

a = 4.917700579 [=(g1/g0)-1]

c = 726.43739626394

Calculation of value F, f & v:

F= 0.485492684339841 0.485493 If g1 = g0 F=0,90892f= 1 [=C36 / (1+a)] 0.16347 If g1 = g0 or f<1, f=1

v= 0.00084453053572 0.000845 If g1 = g0 v=0,550103

[=1/90 + 5 x a/1008-(1+a)3/c]

[=215/2772 + 51 x a/1232 + (60/7 + 225 x a/14 + 75 x a2/7 + 5 x a3/2)/c]

[=31/6930 + 128 x a /45045 + (6/7 + 15 x a/7 + 12 x a2/7 + 5 x a3/11)/c]

[=533/30240 + 653 x a/73920 + (1/2 + 33 x a/14 + 39 x a2/28 + 25 x a3/84)/c]

[=29/3780 + 3 x a/704 - (1/2 + 33 x a/14 + 81 x a2/28 + 13 x a3/12)/c]

[=31/6048 + 1763 x a/665280 + (1/2 + 6 x a/7 + 15 x a2/28 + 5 x a3/42)/c]

[=1/2925 + 71 x a/300300 + (8/35 + 18 x a/35 + 156 x a2/385 + 6 x a3/55)/c]

[=761/831600+937 x a/1663200 + (1/35 + 6 x a/35 + 11 x a2/70 + 3 x a3/70)/c]

[=197/415800 + 103 x a/332640 - (1/35 + 6 x a/35 + 17 x a2/70 + a3/10)/c]

[=233/831600+97 x a/544400 + (1/35 + 3 x a/35 + a2/14 + 2 x a3/105)/c]

[=(C1 x C7 X C12 + C2 x C8 x C3 + C3 x C8 x C2 - (C32 x C7 + C82 x C1 + C22 x C12)]

[=(C4 x C7 x C12 + C2 x C8 x C13 + C3 x C8 x C9 - (C13 x C7 x C3 + C82 x C4 + C12 x C2 x C9))/C16]

[=(C5 x C7 x C12 + C2 x C8 x C14 + C3 x C8 x C10 - (C14 x C7 x C3 + C82 x C5 + C12 x C2 x C10))/C16]

[=(C6 x C7 x C12 + C2 x C8 x C15 + C3 x C8 x C11 - (C15 x C7 x C3 + C82 x C6 + C12 x C2 x C11))/C16]

[=(C1 x C9 x C12 + C4 x C8 x C3 + C3 x C13 x C2 - (C32 x C9 + C13 x C8 x C1 + C12 x C4 x C2))/C16]

[=(C1 x C10 x C12 + C5 x C8 x C3 + C3 x C14 x C2 - (C32 x C10 + C14 x C8 x C1 + C12 x C5 x C2))/C16]

[=(C1 x C11 x C12 + C6 x C8 x C3 + C3 x C15 x C2 - (C32 x C11 + C15 x C8 x C1 + C12 x C6 x C2))/C16]

[=(C1 x C7 x C13 + C2 x C9 x C3 + C4 x C8 x C2 - (C3 x C7 x C4 + C8 x C9 x C1 + C22 x C13))/C16]

[=(C1 x C7 x C14 + C2 x C10 x C3 + C5 x C8 x C2 - (C3 x C7 x C5 + C8 x C10 x C1 + C22 x C14))/C16]

[=(C1 x C7 x C15 + C2 x C11 x C3 + C6 x C8 x C2 - (C3 x C7 x C6 + C8 x C11 x C1 + C22 x C15))/C16

[=-(c/4)0,25]

[=-(c/4)0,5]

[=-(c/4)0,75]

[=-C18 x (c/4)0,75]

[=43,68 x (h/h0)4]

[=-E6/((c/2,73)0,25 x ((1+a)3)/c)

[=E4/((c/2,73)0,25 x (1+a)3)]

Tel. :+31 (0) 168 387410Fax.:+31 (0) 168 387420E-Mail : [email protected]: www.pff-group.com

PFF Europe B.V.Wielewaalweg 4

4791 PD KlundertThe Netherlands