chapter 1 - leaching continuous countercurrent
TRANSCRIPT
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LEACHING
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Introduction
Leaching / solid extraction methods of removingone constituent from a solid by means of a liquidsolvent.
Examples:1) Extraction of oil from soybean flakes2) Extraction of coconut milk from coconut
The amount of soluble material removed is often
greater than in ordinary filtration washing The granular feed solids may disintegrate in pulp or
mush wheb their content of soluble material isremoved.
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Principle of ContinuousCountercurrent Leaching
The most important method of leaching is the continuous
countercurrent method suing stages.
The solid is not moved physically from stage to stage
The liquids is being moved from stage to stage
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V phase = the liquid phase (from stage N to stage 1)
L phase = the liquid carried with the solid (from stage 1 to stage N)
Exhausted solids leave Stage N
Concentrated solution overflow from Stage 1
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Equilibrium
Equilibrium is attained when the solute iscompletely dissolved and the concentration of the
solution formed is uniform.
The concentration of the liquid retained by the
solid leaving any stage is the same as that of the
liquid overflow from the same stage.
The equilibrium relationship is simply xe= y.
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Operating Line
Total mass balance:
Solute:
Operating line equation:
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Number of Ideal Stages for ConstantUnderflow
Use McCabe Thiele Method if the operating line is straight
In leaching, the operating line is always straight
The equilibrium line is on 450 line.
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EXAMPLE 1
Oil is to be extracted from meal by means of benzene
using a continuous countercurrent extractor. The unit is to
treat 1,000 kg of meal (based on completely exhaustedsolid) per hour. The untreated meal contains 400 kg of oil
and is contaminated with 25kg of benzene. The fresh
solvent mixture contains 10kg of oil and 655 kg of
benzene. The exhausted solids are to contain 60kg of
unextracted oil. Experiments carried out under conditions
identical with those of the projected battery show that the
solution retained depends on the concentration of the
solution, as shown in Table 23.1.
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Find
(a) the concentration of the strong solution, or extract;
(b) the concentration of the solution adhering to the extracted
solids;(c) the mass of solution leaving with the extracted meal;
(d) the mass of extract;
(e) the number of stages required.
All quantities are given on an hourly basis.
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Solution
Let x and y be the mass fractions of oil in the underflow and
overflow solutions. At the solvent inlet,
Determine the amount and composition of the solution in the spent
solids by trial. IfXb= 0.1, the solution retained, from Table 23.1,
is 0.505 kg/kg. Then
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From Table 23.1, the solution retained is 0.507 kg/kg:
Benzene in the underflow atLbis 507 - 60 = 447 kg/h.At the solid inlet,
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e) Determine the inlet and exit concentrations for the first stage and
locate the operating line for the remaining stages.
Sincex1= ya= 0.60, solution retained is 0.595 kg/kg solid.
Overall material balance:
Oil balance:
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The pointx1= 0.60, y2= 0.408 is at one end of the operating line
for the remaining stages.
To determine an intermediate point on the operating line, choose
xn= 0.30.
By an overall balance,
An oil balance gives
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The pointsxn,xn+1,xa, yaandxb, ybdefine a slightly curved
operating line, as shown in Fig. 23.3.
Four ideal stages are required.