chapter 07crs 10ed

38
Slide 1 of 41 Copyright © 2011 Pearson Canada Inc. When heat is absorbed by ice (the system) it melts. The quantity q for the system is 1. positive. 2. negative. 3. 0

Upload: ralph-john-ugalino

Post on 14-Feb-2016

36 views

Category:

Documents


0 download

DESCRIPTION

h

TRANSCRIPT

Page 1: Chapter 07crs 10ed

Slide 1 of 41 Copyright © 2011 Pearson Canada Inc.

When heat is absorbed by ice (the system) it melts. The quantity q for the system is

1. positive.

2. negative.

3. 0

Page 2: Chapter 07crs 10ed

Slide 2 of 41 Copyright © 2011 Pearson Canada Inc.

When heat is absorbed by ice (the system) it melts. The quantity q for the system is

1. positive.

2. negative.

3. 0

Catch: Photo of Ice page 498

Page 3: Chapter 07crs 10ed

Slide 3 of 41 Copyright © 2011 Pearson Canada Inc.

When potassium chlorate decomposes it produces oxygen gas. From the system’s point of view (which is the convention), w is

1. positive.

2. negative.

3. No work done.

Page 4: Chapter 07crs 10ed

Slide 4 of 41 Copyright © 2011 Pearson Canada Inc.

1. positive.

2. negative.

3. No work done.

When potassium chlorate decomposes it produces oxygen gas. From the system’s point of view (which is the convention), w is

Page 5: Chapter 07crs 10ed

Slide 5 of 41 Copyright © 2011 Pearson Canada Inc.

Heat is added to the container below while being allowed to expand freely against atmospheric pressure. The temperature and pressure, however, remain constant before and after.

ΔU is,

1. positive.

2. negative.

3. 0

Page 6: Chapter 07crs 10ed

Slide 6 of 41 Copyright © 2011 Pearson Canada Inc.

Heat is added to the container below while being allowed to expand freely against atmospheric pressure. The temperature and pressure, however, remain constant before and after.

ΔU is,

1. positive.

2. negative.

3. 0

Page 7: Chapter 07crs 10ed

Slide 7 of 41 Copyright © 2011 Pearson Canada Inc.

For the following reaction:

2 H2 (g) + O2 (g) g H2O (l) ∆Hº = -572 kJ What is the work associated with this reaction at 25ºC?

1.  7.4 kJ

2.  -7.4 kJ

3.  5.0 kJ

4.  -5.0 kJ

5.  2.5 kJ

Page 8: Chapter 07crs 10ed

Slide 8 of 41 Copyright © 2011 Pearson Canada Inc.

For the following reaction:

2 H2 (g) + O2 (g) g H2O (l) ∆Hº = -572 kJ What is the work associated with this reaction at 25ºC?

1.  7.4 kJ

2.  -7.4 kJ

3.  5.0 kJ

4.  -5.0 kJ

5.  2.5 kJ

Page 9: Chapter 07crs 10ed

Slide 9 of 41 Copyright © 2011 Pearson Canada Inc.

The volume of the Pacific Ocean is about 300 km3. Without the use of a calculator, estimate the heat that is required to raise the temperature of the Pacific Ocean by 1 oC (assume the density of water is 1 g cm-3 and the specific heat is 4 J g-1 oC-1.

4. ~1018 J

1. ~103 J

2. ~106 J

3. ~1012 J

5. ~1025 J

Page 10: Chapter 07crs 10ed

Slide 10 of 41 Copyright © 2011 Pearson Canada Inc.

The volume of the Pacific Ocean is about 300 km3. Without the use of a calculator, estimate the heat that is required to raise the temperature of the Pacific Ocean by 1 oC (assume the density of water is 1 g cm-3 and the specific heat is 4 J g-1 oC-1.

4. ~1018 J

1. ~103 J

2. ~106 J

3. ~1012 J

5. ~1025 J

Page 11: Chapter 07crs 10ed

Slide 11 of 41 Copyright © 2011 Pearson Canada Inc.

In 1 minute the sun shines about 40 kJ m-2 of energy on Earth’s surface and about 1018 J is required to raise the temperature of the Pacific by 1 oC. Assuming that all of the sun’s energy is absorbed, how long must the sun shine

1. 4x1021 min

2. 2.5x1011 min

3. 2.5x105 min

4. 2.5x10-5 min

5. 4x10-10 min

Where does the energy come from to heat the ocean?

on the Pacific to raise its temperature by 1 oC? The area of the Pacific ocean is about 100 km2.

Page 12: Chapter 07crs 10ed

Slide 12 of 41 Copyright © 2011 Pearson Canada Inc.

In 1 minute the sun shines about 40 kJ m-2 of energy on Earth’s surface and about 1018 J is required to raise the temperature of the Pacific by 1 oC. Assuming that all of the sun’s energy is absorbed, how long must the sun shine

1. 4x1021 min

2. 2.5x1011 min

3. 2.5x105 min

4. 2.5x10-5 min

5. 4x10-10 min

Where does the energy come from to heat the ocean?

on the Pacific to raise its temperature by 1 oC? The area of the Pacific ocean is about 100 km2.

Page 13: Chapter 07crs 10ed

Slide 13 of 41 Copyright © 2011 Pearson Canada Inc.

The figure below shows the heating curve for water. It traces the changes in temperature as ice, initially at -20 oC, is gradually heated to produce liquid water at +20 oC. When the ice (the system) melts,

1.  Temperature remains constant, therefore no heat is being added to or removed from the system during the melting of the ice.

2.  Although T is constant, heat is added to convert H2O(s) to H2O(l)

3.  Although T is constant, heat is removed to to convert H2O(s) to H2O(l)

Page 14: Chapter 07crs 10ed

Slide 14 of 41 Copyright © 2011 Pearson Canada Inc.

The figure below shows the heating curve for water. It traces the changes in temperature as ice, initially at -20 oC, is gradually heated to produce liquid water at +20 oC. When the ice (the system) melts,

1.  Temperature remains constant, therefore no heat is being added to or removed from the system during the melting of the ice.

2.  Although T is constant, heat is added to convert H2O(s) to H2O(l)

3.  Although T is constant, heat is removed to to convert H2O(s) to H2O(l)

Page 15: Chapter 07crs 10ed

Slide 15 of 41 Copyright © 2011 Pearson Canada Inc.

The figure below shows the cooling curve for water. It traces the changes in temperature as water, initially at 20 oC, is gradually cooled to produce ice at -20 oC. When the water (the system) freezes,

1.  the temperature remains constant at 0 oC and the process is endothermic.

2.  the temperature remains constant at 0 oC and the process is exothermic.

3.  the temperature remains constant at 0 oC, thus the process is neither endothermic nor exothermic.

Page 16: Chapter 07crs 10ed

Slide 16 of 41 Copyright © 2011 Pearson Canada Inc.

The figure below shows the cooling curve for water. It traces the changes in temperature as water, initially at 20 oC, is gradually cooled to produce ice at -20 oC. When the water (the system) freezes,

1.  the temperature remains constant at 0 oC and the process is endothermic.

2.  the temperature remains constant at 0 oC and the process is exothermic.

3.  the temperature remains constant at 0 oC, thus the process is neither endothermic nor exothermic.

Page 17: Chapter 07crs 10ed

Slide 17 of 41 Copyright © 2011 Pearson Canada Inc.

You take two frozen steaks and put them into room temperature water for a few hours to thaw. The heat gained by the steak (system) equals the heat lost by the water (surroundings). The best equation to express this, where subscript ‘s’ refers to steak and the subscript w refers to the water, is,

w w w s s s1. s m T = s m TΔ Δ

w w w s s s2. s m T = s m TΔ − Δ

w w w s s s3. s m T = s m T− Δ Δ

Page 18: Chapter 07crs 10ed

Slide 18 of 41 Copyright © 2011 Pearson Canada Inc.

You take two frozen steaks and put them into room temperature water for a few hours to thaw. The heat gained by the steak (system) equals the heat lost by the water (surroundings). The best equation to express this, where subscript ‘s’ refers to steak and the subscript w refers to the water, is,

w w w s s s1. s m T = s m TΔ Δ

w w w s s s2. s m T = s m TΔ − Δ

w w w s s s3. s m T = s m T− Δ Δ

Page 19: Chapter 07crs 10ed

Slide 19 of 41 Copyright © 2011 Pearson Canada Inc.

200 g Te (100 oC)

100 g H2O 25 oC

50 oC

What is the heat capacity of Tellurium? Use 4 J g-1 oC-1 for the heat capacity of water.

2Te H Oq = q−

1. 0.5 J g-1 oC-1

2. 1 J g-1 oC-1

3. 2 J g-1 oC-1

4. 4 J g-1 oC-1

5. 10 J g-1 oC-1

Catch Figure 7-3 here

Page 20: Chapter 07crs 10ed

Slide 20 of 41 Copyright © 2011 Pearson Canada Inc.

200 g Te (100 oC)

100 g H2O 25 oC

50 oC

What is the heat capacity of Tellurium? Use 4 J g-1 oC-1 for the heat capacity of water.

2Te H Oq = q−

1. 0.5 J g-1 oC-1

2. 1 J g-1 oC-1

3. 2 J g-1 oC-1

4. 4 J g-1 oC-1

5. 10 J g-1 oC-1

Page 21: Chapter 07crs 10ed

Slide 21 of 41 Copyright © 2011 Pearson Canada Inc.

qP = 250 kJ

T=300 K

V2= 0.110 m3

1x105 Pa

Determine ΔH and ΔU for the reaction and conditions depicted below. Note: 1 Pa = 1 N m-2.

1. 250 kJ, 251 kJ

ΔH ΔU

2. 250 kJ, 249 kJ

3. -250 kJ, -251 kJ

4. -250 kJ, -249 kJ

5. -250 kJ, -250 kJ

V1= 0.120 m3

Page 22: Chapter 07crs 10ed

Slide 22 of 41 Copyright © 2011 Pearson Canada Inc.

qP = 250 kJ

T=300 K

V2= 0.110 m3

1x105 Pa

Determine ΔH and ΔU for the reaction and conditions depicted below. Note: 1 Pa = 1 N m-2.

1. 250 kJ, 251 kJ

ΔH ΔU

2. 250 kJ, 249 kJ

3. -250 kJ, -251 kJ

4. -250 kJ, -249 kJ

5. -250 kJ, -250 kJ

V1= 0.120 m3

Page 23: Chapter 07crs 10ed

Slide 23 of 41 Copyright © 2011 Pearson Canada Inc.

Ice (the system) melting is

1. an exothermic process.

2. an endothermic process.

3.  neither exothermic nor endothermic since the temperature of the system remains constant (0 oC at 1 atm).

Note: a bit tricky perhaps until chapter 13.

Catch: Photo of Ice page 498

Page 24: Chapter 07crs 10ed

Slide 24 of 41 Copyright © 2011 Pearson Canada Inc.

Ice (the system) melting is

1. an exothermic process.

2. an endothermic process.

3.  neither exothermic nor endothermic since the temperature of the system remains constant (0 oC at 1 atm).

Note: a bit tricky perhaps until chapter 13.

Catch: Photo of Ice page 498

Page 25: Chapter 07crs 10ed

Slide 25 of 41 Copyright © 2011 Pearson Canada Inc.

The equation for the combustion of butane is,

Which one of the following generates the least heat?

4 10 2 2 213C H (g) + O (g) 4CO (g) + 5H O(g)2

1. Burning one mole of butane in excess oxygen.

2. Reacting one mole of oxygen with excess butane.

3. Producing one mole of carbon dioxide by burning butane.

4. Producing one mole of water by burning butane.

5. Burning 0.25 moles of butane with excess oxygen.

Page 26: Chapter 07crs 10ed

Slide 26 of 41 Copyright © 2011 Pearson Canada Inc.

The equation for the combustion of butane is,

Which one of the following generates the least heat?

4 10 2 2 213C H (g) + O (g) 4CO (g) + 5H O(g)2

1. Burning one mole of butane in excess oxygen.

2. Reacting one mole of oxygen with excess butane.

3. Producing one mole of carbon dioxide by burning butane.

4. Producing one mole of water by burning butane.

5. Burning 0.25 moles of butane with excess oxygen.

Page 27: Chapter 07crs 10ed

Slide 27 of 41 Copyright © 2011 Pearson Canada Inc.

The chemical reaction representing aerobic respiration is,

6 12 6 2 2 2C H O (s) + 6O (g) 6CO (g) + 6H O(g)→

and is the reverse of photosynthesis. This reaction is exothermic by ~2500 kJ per mole of glucose. A small child exhales about 3 moles of CO2 in a 24 hour period, what is the energy change associated with the photosynthesis reaction required to convert this amount of CO2 back to glucose?

1. 5000 kJ

2. -5000 kJ

3. -2500 kJ

4. 1250 kJ

5. -1250 kJ

Page 28: Chapter 07crs 10ed

Slide 28 of 41 Copyright © 2011 Pearson Canada Inc.

The chemical reaction representing aerobic respiration is,

6 12 6 2 2 2C H O (s) + 6O (g) 6CO (g) + 6H O(g)→

and is the reverse of photosynthesis. This reaction is exothermic by ~2500 kJ per mole of glucose. A small child exhales about 3 moles of CO2 in a 24 hour period, what is the energy change associated with the photosynthesis reaction required to convert this amount of CO2 back to glucose?

1. 5000 kJ

2. -5000 kJ

3. -2500 kJ

4. 1250 kJ

5. -1250 kJ

Page 29: Chapter 07crs 10ed

Slide 29 of 41 Copyright © 2011 Pearson Canada Inc.

Given the heats of formation of the potential products of the Ostwald process, which reaction is most exothermic?

3 2 2 23 1 31. NH (g) + O (g) N (g) + H O(g)4 2 2

3 2 2 21 32. NH (g) + O (g) N O(g) + H O(g)2 2

3 2 25 33. NH (g) + O (g) NO(g) + H O(g)4 2

3 2 2 27 34. NH (g) + O (g) NO (g) + H O(g)4 2

ΔH / kJ mol-1

N2 0

N2O 82.1

NO 90.2

NO2 33.2

Page 30: Chapter 07crs 10ed

Slide 30 of 41 Copyright © 2011 Pearson Canada Inc.

1. NH3(g) + 34

O2(g) ! 12

N2(g) + 32

H2O(g)

3 2 2 21 32. NH (g) + O (g) N O(g) + H O(g)2 2

3 2 25 33. NH (g) + O (g) NO(g) + H O(g)4 2

3 2 2 27 34. NH (g) + O (g) NO (g) + H O(g)4 2

ΔH / kJ mol-1

N2 0

N2O 82.1

NO 90.2

NO2 33.2

Given the heats of formation of the potential products of the Ostwald process, which reaction is most exothermic?

Page 31: Chapter 07crs 10ed

Slide 31 of 41 Copyright © 2011 Pearson Canada Inc.

3 2 2 21. 4NH (g) + 3O (g) 2N (g) + 6H O(g)→

3 2 2 22. 2NH (g) + 2O (g) N O(g) + 3H O(g)→

3 2 23. 4NH (g) + 5O (g) 4NO(g) + 6H O(g)→

3 2 2 24. 4NH (g) + 7O (g) 4NO (g) + 6H O(g)→

ΔH / kJ mol-1

N2 0

N2O 82.1

NO 90.2

NO2 33.2

Given the heats of formation of the potential products of the Ostwald process, which reaction is most exothermic?

NH3 = -46.11kJ/mole

Page 32: Chapter 07crs 10ed

Slide 32 of 41 Copyright © 2011 Pearson Canada Inc.

3 2 2 21. 4NH (g) + 3O (g) 2N (g) + 6H O(g)→

3 2 2 22. 2NH (g) + 2O (g) N O(g) + 3H O(g)→

3 2 23. 4NH (g) + 5O (g) 4NO(g) + 6H O(g)→

3 2 2 24. 4NH (g) + 7O (g) 4NO (g) + 6H O(g)→

ΔH / kJ mol-1

N2 0

N2O 82.1

NO 90.2

NO2 33.2

Given the heats of formation of the potential products of the Ostwald process, which reaction is most exothermic?

NH3 = -46.11 kJ/mole

Page 33: Chapter 07crs 10ed

Slide 33 of 41 Copyright © 2011 Pearson Canada Inc.

The equations for the complete and incomplete combustion of octane are given below.

8 18 2 2 225C H (l) + O (g) 8CO (g) + 9H O(l)2

8 18 2 217C H (l) + O (g) 8CO(g) + 9H O(l)2

ΔHf / kJ mol-1

CO -111

CO2 -394 Which reaction is more exothermic and by how much?

1. Incomplete by 283 kJ mol-1.

2. Incomplete by 2264 kJ mol-1.

3. Complete by 2264 kJ mol-1.

4. Complete by 283 kJ mol-1.

5. Complete by 505 kJ mol-1.

Page 34: Chapter 07crs 10ed

Slide 34 of 41 Copyright © 2011 Pearson Canada Inc.

The equations for the complete and incomplete combustion of octane are given below.

8 18 2 2 225C H (l) + O (g) 8CO (g) + 9H O(l)2

8 18 2 217C H (l) + O (g) 8CO(g) + 9H O(l)2

ΔHf / kJ mol-1

CO -111

CO2 -394 Which reaction is more exothermic and by how much?

1. Incomplete by 283 kJ mol-1.

2. Incomplete by 2264 kJ mol-1.

3. Complete by 2264 kJ mol-1.

4. Complete by 283 kJ mol-1.

5. Complete by 505 kJ mol-1.

Page 35: Chapter 07crs 10ed

Slide 35 of 41 Copyright © 2011 Pearson Canada Inc.

Two equations incomplete combustion of butane are given below.

4 10 2 25B. C H (g) + O (g) 8C(graph) + 5H O(l)2

4 10 2 29A. C H (g) + O (g) 4CO(g) + 5H O(l)2

Given that the heat of formation of CO(g) is -111 kJ mol-1, which reaction is more exothermic and by how much?

1. Reaction A by 111 kJ mol-1.

2. Reaction B by 111 kJ mol-1.

3. Reaction A by 444 kJ mol-1.

4. Reaction B by 444 kJ mol-1.

5. Not enough information to answer.

ΔHf = -111 kJ mol-1

Page 36: Chapter 07crs 10ed

Slide 36 of 41 Copyright © 2011 Pearson Canada Inc.

Two equations incomplete combustion of butane are given below.

4 10 2 25B. C H (g) + O (g) 8C(graph) + 5H O(l)2

4 10 2 29A. C H (g) + O (g) 4CO(g) + 5H O(l)2

Given that the heat of formation of CO(g) is -111 kJ mol-1, which reaction is more exothermic and by how much?

1. Reaction A by 111 kJ mol-1.

2. Reaction B by 111 kJ mol-1.

3. Reaction A by 444 kJ mol-1.

4. Reaction B by 444 kJ mol-1.

5. Not enough information to answer.

ΔHf = -111 kJ mol-1

Page 37: Chapter 07crs 10ed

Slide 37 of 41 Copyright © 2011 Pearson Canada Inc.

+

Given the bond energies below, estimate the enthalpy change for the addition of Br across the double bond in ethene.

C—C 350 kJ mol-1

C=C 600 kJ mol-1

C—Br 300 kJ mol-1

Br—Br 200 kJ mol-1

1. 150 kJ

2. -150 kJ

3. 220 kJ

4. -220 kJ

5. Not enough data to determine ΔrH

Page 38: Chapter 07crs 10ed

Slide 38 of 41 Copyright © 2011 Pearson Canada Inc.

+

Given the bond energies below, estimate the enthalpy change for the addition of Br across the double bond in ethene.

C—C 350 kJ mol-1

C=C 600 kJ mol-1

C—Br 300 kJ mol-1

Br—Br 200 kJ mol-1

1. 150 kJ

2. -150 kJ

3. 220 kJ

4. -220 kJ

5. Not enough data to determine ΔrH