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medication exercise diet

10 6 5

12 8 9

9 3 12

15 0 8

13 2 4

total 59 19 38

sample mean 11.8

Anova: Single Factor

SUMMARY

Groups Count Sum Average Variance

medication 5 59 11.8 5.7

exercise 5 19 3.8 10.2

diet 5 38 7.6 10.3

ANOVA

Source of Variation SS df MS F

Between Groups 160.1333 2 80.06667 9.167939

Within Groups 104.8 12 8.733333

Total 264.9333 14

F bigger than F crit, then rejct null hypothesis.

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P-value F crit

0.003831 3.885293835

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NAME : NUR HIKMAHANA BINTI BAHAMAN

placebo low high

3 5 7

2 2 4

1 4 5

1 2 34 3 6

Anova: Single Factor

SUMMARY

Groups Count Sum Average Variance

placebo 5 11 2.2 1.7

low 5 16 3.2 1.7

high 5 25 5 2.5

ANOVA

Source of Variatio SS df MS F P-value F crit

Between Groups 20.13333 2 10.06667 5.118644 0.024694 3.885294

Within Groups 23.6 12 1.966667

Total 43.73333 14

F calculated, 5.11864 bigger than F critical, 3.88529. so, we rejct null hypothesis. This is

enough evidence to support claim that there is difference among the mean.

P-value smaller than significant level (alpha)

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A B C D

22.7 38.7 31.8 30.6

25.6 40.4 34.4 33.7

43.2 56.3 19.2 49.231.6 46.6 24.4 39.6

8.6 47.7

23.6 46.4

37.2

29.4

Anova: Single Factor

SUMMARY

Groups Count Sum Average Variance

A 4 123.1 30.775 82.34917

B 4 182 45.5 63.36667

C 6 142 23.66667 85.77067

D 8 313.8 39.225 61.21357

ANOVA

Source of Varia SS df MS F P-value F crit

Between G 1422.11 3 474.0367 6.591493 0.003371 3.159908

Within Gro 1294.496 18 71.91644

Total 2716.606 21

F calculated, 6.5915 bigger than F critical, 3.1599. so, we rejct null hypothesis. This is

enough evidence to support claim that there is difference among the mean.

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Akmar Nelson Garneson

8 8 10

10 9 9

9 9 10

11 8 11

10 10 9

Anova: Single Factor

SUMMARY

Groups Count Sum Average Variance

Akmar 5 48 9.6 1.3

Nelson 5 44 8.8 0.7

Garneson 5 49 9.8 0.7

ANOVA

Source of Variation SS df MS F P-value F crit

Between Groups 2.8 2 1.4 1.555556 0.250789 3.885294

Within Groups 10.8 12 0.9

Total 13.6 14

since F calculated, 1.5556 is smaller than F critical, 3.8853, then we fail to reject

null hypothesis. This is enough evidence to support null hypothesis that all

means population are the same.

jadual 2 : keputusan (dalam minit) bagi ketiga-tiga pelajar.

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8/2/2019 Asmnt Statistic ~ Hikmah

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PAST YEAR MAY 2010

A B C

3 10 8

6 12 3

7 11 2

4 14 5

Anova: Single Factor

SUMMARY

Groups Count Sum Average Variance

A 4 20 5 3.333333

B 4 47 11.75 2.916667

C 4 18 4.5 7

ANOVASource of Varia SS df MS F P-value F crit

Between G 131.1667 2 65.58333 14.84906 0.001411 8.021517

Within Gro 39.75 9 4.416667

Total 170.9167 11