# 1 polynomial functions exploring polynomial functions exploring polynomial functions –examples...

Post on 28-Dec-2015

226 views

Embed Size (px)

TRANSCRIPT

Polynomial FunctionsExploring Polynomial FunctionsExamplesModeling Data with Polynomial FunctionsExamples

x03569111214y4231262117151922

Polynomials and Linear FactorsStandard FormExampleFactored FormExamplesFactors and ZerosExamples

Writing a polynomial in standard formYou must multiply:(x + 1)(x+2)(x+3)X3 + 6x2 + 11x + 6

2x3 + 10x2 + 12x2x(x2 + 5x +6)

Factor TheoremThe expression x-a is a linear factor of a polynomial if and only if thevalue a is a zero of the related polynomial function.

Factors and Zeros-3-2-10123(x (-3)) or (x + 3)(x (-2)) or (x + 2)(x (-1)) or (x + 1)(x 0) or x(x 1)(x 2)(x 3)ZEROSFACTORS

Dividing PolynomialsLong DivisionSynthetic Division

Long DivisionThe purpose of this type of division is to use one factor to find another.440Just as 4 finds the 10)x - 1x3 + 6x2 -6x - 1The (x-1) finds the (x2 + 7x + 1)

Synthetic DivisionWhen dividing by x a, use synthetic division.The Remainder Theorem

The Remainder TheoremWhen using Synthetic Division, the remainder is the value of f(a).This method is as good as PLUGGING IN, but may be faster.

Solving Polynomial EquationsSolving by GraphingSolving by Factoring

Solving by GraphingSet equation equal to 0, then substitute y for 0. Look at the x-intercepts. (Zeros)Let the left side be y1and let the right side be y2. (Very much like solving a system of equations by graphing). Look at the points of intersection.

Solving by FactoringSum of two cubes

(a3 + b3) = (a + b)(a2 ab + b2)

Difference of two cubes

(a3 b3) = (a b)(a2 + ab + b2)

More on FactoringIf a polynomial can be factored into linear or quadratic factors, then it can be solved using techniques learned from earlier chapters.Solving a polynomial of degrees higher than 2 can be achieved by factoring.

Theorems about RootsRational Root TheoremIrrational Root TheoremImaginary Root Theorem

Rational Root TheoremWhat are Rational Roots?Ps and Qs . ;)Using the calculator to speed up the process.

And the Rational Roots are..P includes all of the factors of the constant.Q includes all of the factorsof the leading coefficient.f(x) = x3 13x - 12p = 12q = 1The possible rational roots are:

Test the Possible RootsIn this case all roots are real and rational, but you need onlyto find one rational root. This will become clear later.

Since -1, -3, and 4 are the Roots,

(x + 1), (x + 3), and (x 4)

are the factors.Multiply to show that

(x+1)(x+3)(x-4) = x3 13x 12 (x+1)(x2 x 12) x3 x2 12x +x2 x 12 x3 13x 12

Irrational Root TheoremThese are called CONJUGATES.

Imaginary Root TheoremThese are called CONJUGATES.

The Fundamental Theorem of AlgebraIf P(x) is a polynomial of degree with complex coefficients, then P(x) = 0 has at least one complex root.

A polynomial equation with degree n will have exactly n roots; the related polynomial function will have exactly n zeros.

The Binomial TheoremBinomial Expansion and Pascals Triangle

The Binomial Theorem

PASCALS TRIANGLE11 11 2 1 1 3 3 11 4 6 4 1 1 5 10 10 5 11 6 15 20 15 6 11 7 21 35 35 21 7 11 8 28 56 70 56 28 8 11 9 36 84 126 126 84 36 9 1