1 mendelelian genetics copyright cmassengale. 2 gregor mendel ( 1822-1884) responsible for the laws...

64
1 Mendelelian Genetics copyright cmassengale

Upload: nora-mcbride

Post on 28-Dec-2015

215 views

Category:

Documents


0 download

TRANSCRIPT

1

Mendelelian Genetics

copyright cmassengale

2

Gregor Mendel(1822-1884)

Responsible for the Laws governing

Inheritance of Traits

copyright cmassengale

3

Gregor Johann Mendel

Austrian monkStudied the inheritance of traits in pea plantsDeveloped the laws of inheritanceMendel's work was not recognized until the turn of the 20th century

copyright cmassengale

4

Gregor Johann Mendel

Between 1856 and 1863, Mendel cultivated and tested some 28,000 pea plantsHe found that the plants' offspring retained traits of the parentsCalled the “Father of Genetics"

copyright cmassengale

6

Mendel stated that physical traits are inherited as “particles”Mendel did not know that the “particles” were actually Chromosomes & DNA

Particulate Inheritance

copyright cmassengale

7

Genetic Terminology

Trait - any characteristic that can be passed from parent to offspring Heredity - passing of traits from parent to offspring Genetics - study of heredity

copyright cmassengale

8

Types of Genetic Crosses

Monohybrid cross - cross involving a single traite.g. flower color Dihybrid cross - cross involving two traits e.g. flower color & plant height

copyright cmassengale

9

Punnett Square

Used to help solve genetics problems

copyright cmassengale

10copyright cmassengale

11

Designer “Genes”

Alleles - two forms of a gene (dominant & recessive) Dominant - stronger of two genes expressed in the hybrid; represented by a capital letter (R) Recessive - gene that shows up less often in a cross; represented by a lowercase letter (r)

copyright cmassengale

12

More Terminology

Genotype - gene combination for a trait (e.g. RR, Rr, rr) Phenotype - the physical feature resulting from a genotype (e.g. red, white)

copyright cmassengale

13

Genotype & Phenotype in Flowers

Genotype of alleles:R = red flowerr = yellow flowerAll genes occur in pairs, so 2 alleles affect a characteristicPossible combinations are:

Genotypes RR  Rr rrPhenotypes RED RED  YELLOW

copyright cmassengale

14

Genotypes

Homozygous genotype - gene combination involving 2 dominant or 2 recessive genes (e.g. RR or rr); also called pure  Heterozygous genotype - gene combination of one dominant & one recessive allele    (e.g. Rr); also called hybrid

copyright cmassengale

21

Eight Pea Plant Traits

Seed shape --- Round (R) or Wrinkled (r)Seed Color ---- Yellow (Y) or  Green (y)

Pod Shape --- Smooth (S) or wrinkled (s)Pod Color ---  Green (G) or Yellow (g)Seed Coat Color ---Gray (G) or White (g)Flower position---Axial (A) or Terminal (a)Plant Height --- Tall (T) or Short (t)

Flower color --- Purple (P) or white (p)

copyright cmassengale

22copyright cmassengale

23copyright cmassengale

28

Monohybrid Crosses

copyright cmassengale

29

Trait: Seed ShapeAlleles: R – Round r – WrinkledCross: Round seeds x Wrinkled seeds RR  x  rr

P1 Monohybrid Cross

R

R

rr

Rr

RrRr

Rr

Genotype: RrPhenotype: RoundGenotypicRatio: All alikePhenotypicRatio: All alike

copyright cmassengale

30

P1 Monohybrid Cross Review

Homozygous dominant x Homozygous recessiveOffspring all Heterozygous (hybrids)Offspring called F1 generationGenotypic & Phenotypic ratio is ALL ALIKE

copyright cmassengale

31

Trait: Seed ShapeAlleles: R – Round r – WrinkledCross: Round seeds x Round seeds Rr  x  Rr

F1 Monohybrid Cross

R

r

rR

RR

rrRr

Rr

Genotype: RR, Rr, rrPhenotype: Round & wrinkledG.Ratio: 1:2:1P.Ratio: 3:1

copyright cmassengale

32

F1 Monohybrid Cross Review

Heterozygous x heterozygousOffspring:25% Homozygous dominant RR50% Heterozygous Rr25% Homozygous Recessive rrOffspring called F2 generationGenotypic ratio is 1:2:1Phenotypic Ratio is 3:1

copyright cmassengale

33

What Do the Peas Look Like?

copyright cmassengale

34

…And Now the Test Cross

Mendel then crossed a pure & a hybrid from his F2 generationThis is known as an F2 or test crossThere are two possible testcrosses:Homozygous dominant x HybridHomozygous recessive x Hybrid

copyright cmassengale

35

Trait: Seed ShapeAlleles: R – Round r – WrinkledCross: Round seeds x Round seeds RR  x  Rr

F2 Monohybrid Cross (1st)

R

R

rR

RR

RrRR

Rr

Genotype: RR, RrPhenotype: RoundGenotypicRatio: 1:1PhenotypicRatio: All alike

copyright cmassengale

36

Trait: Seed ShapeAlleles: R – Round r – WrinkledCross: Wrinkled seeds x Round seeds rr  x  Rr

F2 Monohybrid Cross (2nd)

r

r

rR

Rr

rrRr

rr

Genotype: Rr, rrPhenotype: Round & WrinkledG. Ratio: 1:1P.Ratio: 1:1

copyright cmassengale

37

F2 Monohybrid Cross Review

Homozygous x heterozygous(hybrid)Offspring:50% Homozygous RR or rr50% Heterozygous RrPhenotypic Ratio is 1:1Called Test Cross because the offspring have SAME genotype as parents

copyright cmassengale

38

Practice Your Crosses

Work the P1, F1, and both F2 Crosses for each of the other Seven Pea Plant Traits

copyright cmassengale

39

Mendel’s Laws

copyright cmassengale

40

Results of Monohybrid Crosses

Inheritable factors or genes are responsible for all heritable characteristics Phenotype is based on Genotype Each trait is based on two genes, one from the mother and the other from the father True-breeding individuals are homozygous ( both alleles) are the same

copyright cmassengale

41

Law of Dominance

In a cross of parents that are pure for contrasting traits, only one form of the trait will appear in the next generation.All the offspring will be heterozygous and express only the dominant trait.RR x rr yields all Rr (round seeds)

copyright cmassengale

42

Law of Dominance

copyright cmassengale

43

Law of Segregation

During the formation of gametes (eggs or sperm), the two alleles responsible for a trait separate from each other.Alleles for a trait are then "recombined" at fertilization, producing the genotype for the traits of the offspring.

copyright cmassengale

44

Applying the Law of Segregation

copyright cmassengale

45

Law of Independent Assortment

Alleles for different traits are distributed to sex cells (& offspring) independently of one another.

This law can be illustrated using dihybrid crosses.

copyright cmassengale

46

Dihybrid Cross

A breeding experiment that tracks the inheritance of two traits.Mendel’s “Law of Independent Assortment”a. Each pair of alleles segregates independently during gamete formationb. Formula: 2n (n = # of heterozygotes)

copyright cmassengale

47

Question:How many gametes will be produced for the

following allele arrangements?

Remember:  2n (n = # of heterozygotes)

 1. RrYy

 2. AaBbCCDd

 3. MmNnOoPPQQRrssTtQq

copyright cmassengale

48

Answer:

1. RrYy: 2n = 22 = 4 gametes RY Ry rY ry

2. AaBbCCDd: 2n = 23 = 8 gametes ABCD ABCd AbCD AbCd aBCD aBCd abCD abCD

3. MmNnOoPPQQRrssTtQq: 2n = 26 = 64 gametes

copyright cmassengale

49

Dihybrid Cross

Traits: Seed shape & Seed colorAlleles: R round r wrinkled Y yellow y green  

RrYy x RrYy

RY Ry rY ry RY Ry rY ry

All possible gamete combinations

copyright cmassengale

50

Dihybrid Cross

RY Ry rY ry

RY

Ry

rY

ry

copyright cmassengale

51

Dihybrid Cross

RRYY

RRYy

RrYY

RrYy

RRYy

RRyy

RrYy

Rryy

RrYY

RrYy

rrYY

rrYy

RrYy

Rryy

rrYy

rryy

Round/Yellow: 9

Round/green: 3

wrinkled/Yellow: 3

wrinkled/green: 1

9:3:3:1 phenotypic ratio

RY Ry rY ry

RY

Ry

rY

ry

copyright cmassengale

53

Test CrossA mating between an individual of unknown genotype and a homozygous recessive individual.Example: bbC__ x bbcc

 BB = brown eyes Bb = brown eyes bb = blue eyes

 CC = curly hair Cc = curly hair cc = straight hair

bC b___

bc

copyright cmassengale

54

Test Cross

Possible results:

bC b___

bc bbCc bbCc

C bC b___

bc bbCc bbccor

c

copyright cmassengale

55

Summary of Mendel’s lawsLAW PARENT

CROSSOFFSPRING

DOMINANCE TT x tt tall x short

100% Tt tall

SEGREGATION Tt x Tt tall x tall

75% tall 25% short

INDEPENDENT ASSORTMENT

RrGg x RrGg round & green x round & green

9/16 round seeds & green pods 3/16 round seeds & yellow pods 3/16 wrinkled seeds & green pods 1/16 wrinkled seeds & yellow pods

copyright cmassengale

56

Incomplete Dominanceand

Codominance

copyright cmassengale

57

Incomplete Dominance

F1 hybrids have an appearance somewhat in between the phenotypes of the two parental varieties.Example: snapdragons (flower)red (RR) x white (rr)

 RR = red flower rr = white flower R

R

r r

copyright cmassengale

58

Incomplete Dominance

Rr

Rr

Rr

Rr

R

R

r

All Rr = pink(heterozygous pink)

produces theF1 generation

r

copyright cmassengale

59

Incomplete Dominance

copyright cmassengale

60

Codominance

Two alleles are expressed (multiple alleles) in heterozygous individuals.Example: blood type

 1. type A = IAIA or IAi 2. type B = IBIB or IBi 3. type AB = IAIB 4. type O = ii

copyright cmassengale

61

Codominance Problem

Example: homozygous male Type B (IBIB) x    heterozygous female Type A (IAi)

IAIB IBi

IAIB IBi

1/2 = IAIB

1/2 = IBi

IB

IA i

IB

copyright cmassengale

62

Another Codominance Problem

Example: male Type O (ii) x female type AB (IAIB)

IAi IBi

IAi IBi

1/2 = IAi

1/2 = IBi

i

IA IB

i

copyright cmassengale

63

Codominance

Question:If a boy has a blood type O and   his sister has blood type AB,   what are the genotypes and   phenotypes of their parents?

boy - type O (ii) X girl - type AB (IAIB)

copyright cmassengale

64

Codominance

Answer:

IAIB

ii

Parents:genotypes = IAi and IBiphenotypes = A and B

IB

IA i

i

copyright cmassengale

65

Sex-linked Traits

Traits (genes) located on the sex chromosomesSex chromosomes are X and YXX genotype for femalesXY genotype for malesMany sex-linked traits carried on X chromosome

copyright cmassengale

66

Sex-linked Traits

Sex Chromosomes

XX chromosome - female

Xy chromosome - male

fruit flyeye color

Example: Eye color in fruit flies

copyright cmassengale

67

Sex-linked Trait Problem

Example: Eye color in fruit flies  (red-eyed male) x (white-eyed female) XRY x XrXrRemember: the Y chromosome in males does not carry traits.RR = red eyedRr = red eyedrr = white eyedXY = maleXX = female

XR

Xr Xr

Y

copyright cmassengale

68

Sex-linked Trait Solution:

XR Xr

Xr Y

XR Xr

Xr Y

50% red eyed  female50% white eyed  male

XR

Xr Xr

Y

copyright cmassengale

69

Female Carriers

copyright cmassengale

70

Genetic Practice Problems

copyright cmassengale

71

Breed the P1 generation

tall (TT) x dwarf (tt) pea plants

T

T

t t

copyright cmassengale

72

Solution:

T

T

t t

Tt

Tt

Tt

Tt All Tt = tall(heterozygous tall)

produces theF1 generation

tall (TT) vs. dwarf (tt) pea plants

copyright cmassengale

73

Breed the F1 generation

tall (Tt) vs. tall (Tt) pea plants

T

t

T t

copyright cmassengale

74

Solution:

TT

Tt

Tt

tt

T

t

T tproduces theF2 generation1/4 (25%) = TT1/2 (50%) = Tt1/4 (25%) = tt1:2:1 genotype 3:1 phenotype

tall (Tt) x tall (Tt) pea plants

copyright cmassengale

75copyright cmassengale